add day 10

day10/both.bas

@@ -0,0 +1,71 @@
+REM Advent of Code 2022: Day 9, part 1
+REM Written in Applesoft BASIC
+
+ 10  GR 
+ 20 CX = 0
+ 22 CY = 14
+ 24 AD = 0
+ 26 X = 1
+ 28 CC = 1
+ 38 ST = 0
+ 40 D = 0
+ 42 SC = 1
+ 44 SM = 20
+ 50  PRINT  CHR$ (4),"OPEN INPUT"
+ 60  PRINT  CHR$ (4),"READ INPUT"
+ 70  ONERR  GOTO 1000
+
+REM Read the next input line into S$.
+
+ 100 S$ = ""
+ 110  GET C$
+ 120  IF C$ < " " GOTO 200
+ 130 S$ = S$ + C$
+ 140  GOTO 110
+
+REM Parse into instruction letter ("a" or "n") and addx parameter N.
+
+ 200 L =  LEN (S$)
+ 205  IF L = 0 GOTO 1000
+ 208  PRINT "> ";S$
+ 210 II$ =  LEFT$ (S$,1)
+ 220  IF L < 6 THEN N = 0
+ 230  IF L > 5 THEN N =  VAL ( RIGHT$ (S$,L - 5))
+ 240 D = 0
+ 250 AD = 0
+
+REM Update the "CRT" based on X-position and X-register.
+
+ 300  COLOR= 0
+ 310  IF  ABS (X - CX) < 2 THEN  COLOR= CX / 5 + 1
+ 320  PLOT CX,CY
+ 330 CX = CX + 1
+ 340  IF CX > 39 THEN CX = 0:CY = CY + 1
+
+REM Run the next cycle. AD != 0 on 2nd cycle of addx.
+
+ 400 CC = CC + 1
+ 410  IF AD = 0 GOTO 450
+ 420 X = X + AD
+ 430 AD = 0
+ 440 D = 1
+ 445  GOTO 500
+ 450  IF II$ = "a" THEN AD = N
+ 460  IF II$ = "n" THEN D = 1
+
+REM Update strength counter, and strength total if necessary.
+REM Otherwise, GOTO 100 for next instruction or 300 for next addx cycle.
+
+ 500 SC = SC + 1
+ 510  IF SC < SM GOTO 530
+ 515 SM = SM + 40
+ 520 ST = ST + CC * X
+ 530  IF D = 1 GOTO 100
+ 550  GOTO 300
+
+REM End of input: print strength and exit.
+
+ 1000  PRINT "STRENGTH: ";ST
+ 1010  PRINT  CHR$ (4),"CLOSE"
+ 1020  END 
+

day10/both.cpp

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+#include <algorithm>
+#include <iostream>
+#include <string>
+#include <tuple>
+#include <vector>
+
+int main()
+{
+    std::vector<std::pair<char, int>> steps;
+
+    while (1) {
+        std::string line;
+        std::getline(std::cin, line);
+        if (std::cin.eof())
+            break;
+
+        int n = line.size() < 6 ? 0 : stoi(line.substr(5));
+        steps.emplace_back(line.front(), n);
+    }
+
+    int cx = 0;
+
+    int cycle = 1;
+    int adding = 0;
+    int X = 1;
+    int strength = 0;
+    for (int i = 0; i < steps.size();) {
+        const auto& [ins, n] = steps[i];
+
+        if (abs(X - cx) < 2)
+            std::cout << '#';
+        else
+            std::cout << '.';
+
+        if (++cx == 40) {
+            std::cout << std::endl;
+            cx = 0;
+        }
+
+        ++cycle;
+
+        if (adding != 0) {
+            X += adding;
+            adding = 0;
+            ++i;
+        } else if (ins == 'a') {
+            adding = n;
+        } else if (ins == 'n') {
+            ++i;
+        }
+
+        if ((cycle - 20) % 40 == 0)
+            strength += cycle * X;
+    }
+
+    std::cout << "strength: " << strength << std::endl;
+
+    return 0;
+}
+